\(\begin{array}{c|c} \text{No. of pets} & 0 & 1 & 2 & 3 & 4 \\ \hline \text{No. of students} & 8 & 4 & 5 & 10 & 3\end{array}\) The table shows the number of pets kept by 30 students in a class. If a student is picked at random ftom the class. What is the probability that he/she kept more than one pet?
- \(\frac{1}{5}\)
- \(\frac{2}{5}\)
-
\(\frac{3}{5}\)
- \(\frac{4}{5}\)
The correct answer is: C
Explanation
pr. (More than one pet)= \(\frac{\text{No. of students with > 1 pet}}{\text{total no. of students}}\)
= \(\frac{5 + 10 + 3}{30}\)
= \(\frac{18}{30}\)
= \(\frac{3}{5}\)