Given that tan x = 1, where 0o \(\geq\) x 90o, evaluate \(\frac{1 – \sin^2 x}{\cos x}\)
- 2\(\sqrt{2}\)
- \(\sqrt{2}\)
-
\(\frac{\sqrt{2}}{2}\)
- \(\frac{1}{2}\)
The correct answer is: C
Explanation
Given tan x = 1x = tan-1(1)
x = 45o
Now, \(\frac{1 - ( \frac{1}{\sqrt{2} )^2}}{\frac{1}{\sqrt{2}}}\)
= \(\frac{1 - \frac{1}{2}}{\frac{1}{2}}\)
= \(\frac{1}{2} + \frac{1}{\sqrt{2}}\)
= \(\frac{1}{2} \times \frac{1}{\sqrt{2}}\)
= \(\frac{\sqrt{2}}{2}\)