\(\begin{array}{c|c} x & 0 & 2 & 4 & 6\\ \hline y & 1 & 2 & 3 & 4\end{array}\).
The table is for the relation y = mx + c where m and c are constants. What is the equation of the line described in the tablet?
- y = 2x
- y = x + 1
- y = x
-
y = \(\frac{1}{2}x + 1\)
The correct answer is: D
Explanation
y = mx + c; when x = 0; y = 11 = m(0) + c; 1 = 0 + c; c = 1
when x = 2; y = 2
2 = m(2) + c; 2 = 2m + c; but c = 1
2 = 2m + 1
2 - 1 = 2m
2m = 1
m = \(\frac{1}{2}\)
y = \(\frac{1}{2}\)x + 1