In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y
-
105o
- 110o
- 130o
- 150o
The correct answer is: A
Explanation
In \(\bigtriangleup\) PQR,Q = S = 75o (Corresponding angle)
R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))
But, y + 75o = 180o (Sum of angles in a straight line)
y = 180 - 75
y = 105o