Given that cos xo = \(\frac{1}{r}\), express tan x in terms of r
- \(\frac{1}{\sqrt{r}}\)
- \(\sqrt{r}\)
- \(\sqrt{r^2 + 1}\)
-
\(\sqrt{r^2 - 1}\)
The correct answer is: D
Explanation
cos xo = \(\frac{1}{r}\); \(\sqrt{r^2 - 1}\)By Pythagoras r2 = 12 + x2 - 1
x = \(\sqrt{r^2 - 1}\)
tan xo = \(\sqrt{r^2 - 1}\)
= \(\sqrt{r^2 - 1}\)