If a number is chosen at random from the set {x: 4 \(\leq x \leq 15\)}. Find the probability that it is a multiple of 3 or a multiple of 4
- \(\frac{1}{12}\)
- \(\frac{5}{12}\)
-
\(\frac{7}{12}\)
- \(\frac{11}{12}\)
The correct answer is: C
Explanation
set = 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
multiple of 3 = 6, 9, 12, 15
multiple of 4 = 4, 8, 12
Prob(multiple of 3 or 4) = Prob(multiple of 3) + pro(multiple of 4)
= \(\frac{4}{12} + \frac{3}{12} = \frac{7}{12}\)