In the diagram /Pq//TS//TU, reflex angle QPS = 245o angle PST = 115o, , STU...

In the diagram /Pq//TS//TU, reflex angle QPS = 245^o angle PST = 115^o, , STU = 65^o and < RPS = x. Find the value of x

The correct answer is: D

< QPR = < STU = 65^o (Corresponding angles)

245 + < QPR = x = 360^o (< s at a point)

i.e. 245 + 65 + x = 360

x = 360 - (245 + 65)

x = 50^o