The nth term of a sequence is Tn = 5 + (n – 1)2. Evaluate T4 – T6
- 30
- 16
-
-16
- -30
The correct answer is: C
Explanation
T4 = 5 + (4 - 1)2; where n = 4= 5 + (3)2 = 5 + 9
= 14
T = 5 + (6 - 1)2
where n = 6
= 5 + (5)2
= 5 + 25 = 30
T4 + T6 = 14 - 30
= -16