Make p the subject of the relation: q = \(\frac{3p}{r} + \frac{s}{2}\)
- p = \(\frac{2q - rs}{6}\)
- p = 2qr - sr - 3
- p = \(\frac{2qr - s}{6}\)
-
p = \(\frac{2qr - rs}{6}\)
The correct answer is: D
Explanation
q = \(\frac{3p}{r} + \frac{s}{2}\)q = \(\frac{6p + rs}{2r}\)
6p + rs = 2qr
6p = 2qr - rs
p = \(\frac{2qr - rs}{6}\)