Find the values of k in the equation 6k2 = 5k + 6
- {\(\frac{-2}{3}, \frac{-3}{2}\)}
-
{\(\frac{-2}{3}, \frac{3}{2}\)}
- {\(\frac{2}{3}, \frac{-3}{2}\)}
- {\(\frac{2}{3}, \frac{3}{2}\)}
The correct answer is: B
Explanation
6k2 = 5k + 66k2 - 5k - 6 = 0
6k2 - 0k + 4k - 6 = 0
3k(2k - 3) + 2(2k - 3) = 0
(3k + 2)(2k - 3) = 0
3k + 2 = 0 or 2k - 3 = 0
3k = -2 or 2k = 3
k = \(\frac{-2}{3}\) or k = \(\frac{3}{2}\)
k = (\(\frac{-2}{3}\), k = \(\frac{3}{2}\))