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Express \(\frac{2}{x + 3} – \frac{1}{x – 2}\) as a simple fraction

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Mathematics WAEC 2013

Express \(\frac{2}{x + 3} – \frac{1}{x – 2}\) as a simple fraction

  • \(\frac{x - 7}{x^2 + x - 6}\) checkmark
  • \(\frac{x - 1}{x^2 + x - 6}\)
  • \(\frac{x - 2}{x^2 + x - 6}\)
  • \(\frac{x - 27}{x^2 + x - 6}\)

The correct answer is: A

Explanation

\(\frac{2}{x + 3} - \frac{1}{x - 2}\) = \(\frac{2(x - 2) - (x - 3)}{(x + 3) (x - 2)}\)

= \(\frac{2x - 4 - x - 3}{x^2 - 2x + 3x - 6}\)

= \(\frac{x -7}{x^2 + x - 6}\)

= \(\frac{x - 7}{x^2 + x - 6}\)
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