A man’s eye level is 1.7m above the horizontal ground and 13m from a vertical pole. If the pole is 8.3m high, calculate, correct to the nearest degree, the angle of elevation of the top of the pole from his eyes.
- 33o
- 32o
-
27o
- 26o
The correct answer is: C
Explanation
tan \(\theta = \frac{opp}{adj} = \frac{6.6}{13}\)tan \(\theta = 0.5077\)
\(\theta\) = tan-1 0.5077
\(\theta = 27^o\)