If 2n = y, Find 2\(^{(2 + \frac{n}{3})}\)
-
4y\(^\frac{1}{3}\)
- 4y\(^-3\)
- 2y\(^\frac{1}{3}\)
- 2y\(^-3\)
The correct answer is: A
Explanation
If 2n = y,then, 2\(^{(2 + \frac{n}{3})}\) = 22 x 2\(^\frac{n}{3}\)
= 4 x (2n)\(^{\frac{1}{3}}\)
But y = 2n, hence
2\(^{(2 + \frac{n}{3})}\) = 4 x y\(^{\frac{1}{3}}\)
= 4y\(^\frac{1}{3}\)