If log2(3x – 1) = 5, find x.

Explanation

Log₂(3x - 1) = 5

Log₂(3x - 1) = Log₂2⁵

Log₂(3x - 1) = Log₂32

3x - 1 = 32

3x = 32 + 1 = 33

x = \(\frac{33}{3}\)

= 11