The perimeter of a sector of a circle of radius 21cm is 64cm. Find the angle of the sector [Take \(\pi = \frac{22}{7}\)]
- 70o
-
60o
- 55o
- 42o
The correct answer is: B
Explanation
Perimeter of a sector= 2r + \(\frac{\theta}{360^o}\) x 2 x \(\frac{22}{7}\) x 21
64 = 2 x 21 + \(\frac{\theta}{360^o}\) x 2 x \(\frac{22}{7}\) x 21
64 = 42 + \(\frac{\theta}{360^o}\) x 44 x 3
64 - 42 = \(\frac{\theta}{360^o}\) x 11 x 3
22 = \(\frac{33\theta}{90}\)
\(\theta = \frac{22 \times 30}{11}\)
= 60o