If x varies inversely as y and y varies directly as z, what is the relationship between x and z?
- x \(\alpha\) z
-
x \(\alpha\) \(\frac{1}{z}\)
- a \(\alpha\) z\(^2\)
- x \(\alpha\) \(\frac{1}{z^2}\)
The correct answer is: B
Explanation
\(x \propto \frac{1}{y}\), y \(\propto\) z
x = \(\frac{k}{y}\)
y = mz
Since y = mz,
x = \(\frac{k}{mz}\), where k and m are constants. Hence,
x \(\propto\) \(\frac{1}{z}\)