Three exterior angles of a polygon are 30(^o), 40(^o) and 60(^o). If the remaining exterior...

Three exterior angles of a polygon are 30\(^o\), 40\(^o\) and 60\(^o\). If the remaining exterior angles are 46\(^o\) each, name the polygon.

The correct answer is: C

Sum of all exterior angles is 360\(^o\)

360\(^o\) (30\(^o\) - 40\(^o\))

360 - (130\(^o\))

230\(^o\)

remaining is 46\(^o\) = \(\frac{230}{46}\) = 5

5 + 3 = 8 sides; Octagon