Make x the subject of the relation d = \(\sqrt{\frac{6}{x} – \frac{y}{2}}\)
- x = \(\frac{6 + 12}{d^2 + y}\)
- x = \(\frac{12}{d^2 - y}\)
- x = \(\frac{12}{y} - 2d^2\)
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x = \(\frac{12}{2d^2 + y}\)
The correct answer is: D
Explanation
d = \(\sqrt{\frac{6}{x} - \frac{y}{2}}\)
\(d^2 = \frac{6}{x} - \frac{y}{2}\)
\(2xd^2 = 12 - xy\)
\(2xd^2 + xy = 12\)
x = \(\frac{12}{2d^2 + y}\)