The diagram shows a circle centre O. if 29 and
- 12\(^o\)
-
15\(^o\)
- 29\(^o\)
- 34\(^o\)
The correct answer is: B
Explanation
SOT = 2 x 46 (< at the centre is twice < at circumference) = 92
2x + 92 = 180( sum of <s of Isos. triangle)
x = \(\frac{180- 92}{2}\) = 44º
< STO = 44º - 29º
= 15\(^o\)