The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at random scored at most 3 goals.
- \(\frac{3}{25}\)
- \(\frac{1}{5}\)
- \(\frac{6}{25}\)
-
\(\frac{2}{5}\)
The correct answer is: D
Explanation
No. of teams that scored at most 3 goals = 3 + 1 + 6 = 10
Hence, probability that a team selected at random scored at most 3 goals
= \(\frac{10}{25}\) = \(\frac{2}{5}\)