Given that Y is 20cm on a bearing of 300\(^o\) from x, how far south of y is x?
-
10cm
- 15cm
- 25cm
- 30cm
The correct answer is: A
Explanation
In \(\bigtriangleup\)YSC, sin 30\(^o\) = \(\frac{YS}{20}\)
|YS| = 20 sin 30\(^o\)
= 20 x 0.5
10m