If 23\(_y\) = 1111\(_{\text{two}}\), find the value of y
- 4
- 5
-
6
- 7
The correct answer is: C
Explanation
23\(_y\) = 1111\(_{\text{two}}\),
2 x y\(^1\) + 3 x y\(^0\) = 1 x 2\(^3\) + 1 x 2\(^1\) + 1 x 2\(^o\)
2y + 3 = 8 + 4 + 2 + 1
2y + 3 = 15
\(\frac{2y}{2}\)
\(\frac{12}{2}\)
y = 6