Simplify: \(\log_{10}\) 6 – 3 log\(_{10}\) 3 + \(\frac{2}{3} \log_{10} 27\)
- 3 \(\log_{10}^2\)
-
\(\log_{10}^2\)
- \(\log_{10}^3\)
- 2 \(\log_{10}^3\)
The correct answer is: B
Explanation
log\(_{10}\) 6 - log\(_{10}\)3\(^3\) + log\(_{10}\) (\(\sqrt[3]{27}\))\(^2\)
= log \(_{10}\) 6 - log \(_{10}\) 27 + log\(_{10}\) 9
= log\(_{10}\) \(\frac{6 \times 9}{27}\)
= log\(_{10}\)2