In XYZ, |YZ| = 32cm, < YXZ 53\(^o\) and XZY = 90\(^o\). Find, correct to the nearest centimetre, |XZ|
- 31 cm
-
25 cm
- 20 cm
- 13 cm
The correct answer is: B
Explanation
Tan 52\(^o\) = \(\frac{32}{\text{|XZ|}}\)
|XZ| = \(\frac{32}{Tan 52^o}\)
= 25cm