If log\(_x\) 2 = 0.3, evaluate log\(_x\) 8.
- 2.4
- 1.2
-
0.9
- 0.6
The correct answer is: C
Explanation
log\(_x\)2 = 0.3
log\(_x\)8 = log\(_x\)2\(^3\) = 3 log\(_x\)2
= 3 x 0.3
= 0.9