Find the angle at which an arc of length 22 cm subtends at the centre of a circle of radius 15cm. [Take \(\pi = \frac{22}{7}\)]
- 70\(^o\)
-
84\(^o\)
- 96\(^o\)
- 156\(^o\)
The correct answer is: B
Explanation
L = \(\frac{\theta}{360} \times 2 \pi r\)
22 = \(\frac{\theta}{360} \times 2 \times \frac{22}{7} \times 15\)
\(\theta = \frac{22 \times 360 \times 7}{2 \times 22 \times 15}\)
\(\theta\) = 84\(^o\)