Find the equation of a straight line passing through the point (1, -5) and having gradient of \(\frac{3}{4}\)
- 3x + 4y - 23 = 0
- 3x + 4y +23 = 0
- 3x - 4y +23 = 0
-
3x - 4y - 23 = 0
The correct answer is: D
Explanation
\(\frac{3}{4} = \frac{y + 5}{x - 1}\)
3(x - 1) = 4(y + 5)
3x - 3 = 4y + 20
3x - 4y - 23 = 0