Solve 3x – 2y = 10 and x + 3y = 7 simultaneously
- x = -4 and y = 1
- x = -1 and y = -4
- x = 1 and y = 4
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x = 4 and y = 1
The correct answer is: D
Explanation
3x - 2y = 10 - - x 3
x + 3y = 7 ---x 2
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9x - 6y = 30
2x + 6y = 14
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\(\frac{11x}{11} \frac{44}{11}\)
x = 4
From x + 3y = 7
3y = 7 - 4
\(\frac{3y}{3}\) = \(\frac{3}{3}\)
y = 1