The first term of a geometric progression (G.P) is 3 and the 5th term is 48. Find the common ratio.
The correct answer is: A
Explanation
T\(_5\) = ar\(^4\)
\(\frac{48}{3} = \frac{3r^4}{3}\)
16 = r\(^4\)
r = \(4\sqrt{16}\)
= 2
The first term of a geometric progression (G.P) is 3 and the 5th term is 48. Find the common ratio.
T\(_5\) = ar\(^4\)
\(\frac{48}{3} = \frac{3r^4}{3}\)
16 = r\(^4\)
r = \(4\sqrt{16}\)
= 2