Make m the subject of the relation k = \(\sqrt{\frac{m – y}{m + 1}}\)
- m = \(\frac{y + k^2}{k^2 + 1}\)
-
m = \(\frac{y + k^2}{1 - k^2}\)
- m = \(\frac{y - k^2}{k^2 + 1}\)
- m = \(\frac{y - k^2}{1 - k^2}\)
The correct answer is: B
Explanation
k = \(\sqrt{\frac{m - y}{m + 1}}\)
k\(^2\) = \(\frac{m - y}{m + 1}\)
k\(^2\)m + k\(^2\) = m - y
k\(^2\) + y = m - k\(^2\)m
\(\frac{k^2 + y}{1 - k^2}\) = m\(\frac{(1 - k^2)}{1 - k^2}\)
m = \(\frac{y + k^2}{1 - k^2}\)