Find the quadratic equation whose roots are \(\frac{1}{2}\) and -\(\frac{1}{3}\)
- 3x\(^2\) + x + 1 = 0
- 6x\(^2\) + x - 1 = 0
- 3x\(^2\) + x - 1 = 0
-
6x\(^2\) - x - 1 = 0
The correct answer is: D
Explanation
x = \(\frac{1}{2}\) and x = \(\frac{-1}{3}\)
(2x - 1) = 0 and (3x + 1) = 0
(2x - 1) (3x + 1) = 0
6x\(^2\) - x - 1 = 0