Find the equation of the line parallel to 2y = 3(x – 2) and passes through the point (2, 3)
- y = \(\frac{2}{3} x - 3\)
- y = \(\frac{2}{3} x - 2\)
-
y = \(\frac{3}{2} x\)
- y = \(\frac{-2}{3} x\)
The correct answer is: C
Explanation
2y = 3(x - 2)
\(\frac{2y}{2} = \frac{3x}{2} - \frac{6}{2}\)
y = \(\frac{3}{2}x - 3\)
m = \(\frac{3}{2}\)
\(\frac{y - y_1}{x - x_1}\) = m
\(\frac{y - 3}{x - 2} = \frac{3}{2}\)
2y - 6 = 3x - 6
\(\frac{2y}{2} = \frac{3x}{2}\)
y = \(\frac{3}{2}\)x