The expression \(\frac{5x + 3}{6x (x + 1)}\) will be undefined when x equals
- {0, 1}
-
{0, -1}
- {-3, -11}
- {-3, 0}
The correct answer is: B
Explanation
6x(x + 1) = 0
When 6x = 0 and
x + 1 = 0
x = 0 and x = -1
(0, -1)