A box contains 12 identical balls of which 5 are red, 4 blue, and the rest are green. If a ball is selected at random from the box, what is the probability that it is green?
- \(\frac{3}{4}\)
- \(\frac{1}{2}\)
- \(\frac{1}{3}\)
-
\(\frac{1}{4}\)
The correct answer is: D
Explanation
No. of red = 5
No. of blue = 4
No. of green = 3
Total = 12
Pr(Green) = \(\frac{3}{12} = \frac{1}{4}\)