Solve: 2\(^{\sqrt{2x + 1}}\) = 32
- 13
- 24
-
12
- 11
The correct answer is: C
Explanation
2\(^{\sqrt{2x + 1}}\) = 32
2\(^{\sqrt{2x + 1}}\) = 2\(^5\)
\(\sqrt{2x + 1}\) = 5
square both sides
2x + 1 = 5\(^2\)
2x + 1 = 25
2x = 25 - 1
2x = 24
x = \(\frac{24}{2}\)
x = 12