If  \(\frac{2}{x-3}\) – \(\frac{3}{x-2}\) = \(\frac{p}{(x-3)(x -2)}\), find p.

Mathematics WAEC 2021

If  \(\frac{2}{x-3}\) – \(\frac{3}{x-2}\) = \(\frac{p}{(x-3)(x -2)}\), find p.

  • 5 - x checkmark
  • - (x + 5)
  • 13 - x
  • - (5x - 13)

The correct answer is: A

Explanation

\(\frac{2}{x-3}\) - \(\frac{3}{x-2}\)

= \(\frac{2(x -2) -3(x - 3)}{(x-3)(x -2)}\)

= \(\frac{2x -4 -3x + 9}{(x-3)(x -2)}\)

= \(\frac{5 - x}{(x-3)(x -2)}\)

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