A man left town am at 10:00 AM and traveled by car to town N at an average speed of 72 km/h.
He spent 2hours for a meeting and returned through town M by bus at an average speed of 40KM/H.
If the distance covered by the bus was 2km longer than that of the car and he arrived at town M at 1 :55PM.
calculate distance from M to N.
Explanation
Time spent traveling = 3 hours 55 minutes - 2 hours
= 1hr 55mins
Let x be the distance from M - N
and t , time spent from M - N
Then t = x / 72
Return time = (23 / 12) - t
(23 / 12) - t = (x + 2) / 40
(23 / 12) - ( x / 72) = (x + 2) / 40
\(\frac{138 - x}{9}\) = \(\frac{x + 2}{5}\)
690 - 5x = 9x + 18
14x = 672
x = 48km