.Find the value of x such that \(\frac{1}{x}\) +\(\frac{4}{3x}\) – \(\frac{5}{6x}\) + 1 = 0
- \(\frac{1}{6}\)
- \(\frac{1}{4}\)
-
\(\frac{-3}{2}\)
- \(\frac{-7}{6}\)
The correct answer is: C
Explanation
\(\frac{1}{x}\) +\(\frac{4}{3x}\) - \(\frac{5}{6x}\) + 1 = 0
using 6x as lcm
→ \(\frac{6+8-5+6x}{6x}\)
→ \(\frac{9+6x}{6x}\) = 0
9+6x = 0
6x = -9
x = \(\frac{-9}{6}\) or \(\frac{-3}{2}\)