In the diagram, ∠POQ = 150 and the radius of the circle PSQR is 4.2cm. [take π = 22/7]
What is the length of the minor arc?
-
11cm
- 15.4cm
- 17.64cm
- 23.10cm
The correct answer is: A
Explanation
\(\frac{θ}{360}\) * 2 * π * r → \(\frac{150 * 2 * 22 * 4.2}{360 x 7}\)
= 11cm