Simplify \(\frac{2-18m^2}{1+3m}\)
- 2[1+3m]
-
2[1-3m]
- 2[1-3m\(^2\)]
- 2[1+3m\(^2\)]
The correct answer is: B
Explanation
\(\frac{2-18m^2}{1+3m}\) = \(\frac{2[1-9m^2]}{1+3m}\)
\(\frac{2[1-3m][1+3m]}{1+3m}\)
2[1-3m]