Solve \(\frac{y+2}{4}\) – \(\frac{y-1}{3}\) > 1
- y < -10
-
y < -2
- y < 2
- y < 10
The correct answer is: B
Explanation
multiply both sides by the LCM
12 x \(\frac{y+2}{4}\) - 12 x \(\frac{y-1}{3}\) >12 x 1
3[y+2] - 4[y-1] > 12
3y + 6 - 4y + 4 > 12
-y + 2 > 12
-y > 12 - 10 = 2
y < -2