The lengths of the parallel sides of a trapezium are 9cm and 12cm. If the area of the trapezium is 105cm\(^2\), find the perpendicular distance between the parallel sides.
- 5cm
- 7cm
-
10cm
- 15cm
The correct answer is: C
Explanation
Area of a trapezium = \(\frac{[a+b]h}{2}\)
105 = \(\frac{[9+12]h}{2}\) β 105 x 2 =21h
h = \(\frac{210}{21}\) β 10cm