Solve \(1 + \sqrt[3]{ x – 3} = 4\)
-
30
- 6
- 12
- 66
The correct answer is: A
Explanation
\(1 + \sqrt [3]{x-3} = 4\)
= \(\sqrt[3]{x - 3} = 4 - 1\)
\(\sqrt[3]{x - 3} = 3 \)
take the cube of both sides
= x - 3 = 27
x = 27 + 3
∴ x = 30