The angle of elevation of the top of a building from a point Z on the ground is 50°. If the height of the building is 124 m, find the distance from Z to the foot of the building.
- 147.78m
-
104.05m
- 161.87m
- 192.91m
The correct answer is: B
Explanation
From the diagram above; Tan\(\theta = \frac{opp}{adj}\)
tan50° = \(\frac{124}{d}\)
d = \(\frac{124}{tan50}\)
therefore, d = 104.05m