If log\(_3^{2x – 1}\) = 5, find the value of x
- 8
- 16
- 64
-
122
The correct answer is: D
Explanation
log\(_3^{2x - 1}\) = 5 in index form becomes 3\(^5\) = 2x - 1
2x - 1 = 243
2x = 243 + 1 = 244
x = \(\frac{244}{2}\) = 122