Given that P is 25 m on a bearing of 330º from Q, how far south of P is Q?
- 25.2 m
-
21.7 m
- 19.8 m
- 18.5 m
The correct answer is: B
Explanation
Sin 60º = \(\frac{d}{25}\)
d = Sin 60º x 25 = 21.6506m ≈ 21.7m