The area of a sector of a circle with radius 7cm is 51.3 cm\(^2\). Calculate, correct to the nearest whole number, the angle of the sector. (Take \(\pi\) = \(\frac{22}{7}\))
- 60\(^0\)
-
120\(^0\)
- 150\(^0\)
- 150\(^0\)
The correct answer is: B
Explanation
Area of a sector = \(\frac{\theta}{360}\) x \(\pi\) r\(^2\)
51.3 = \(\frac{\theta}{360}\) x \(\frac{22}{7}\) x 7 x 7
\(\theta\) = \(\frac{51.3 \times 360}{22 \times 7}\) = 119.9 ≈ 120º to the nearest whole number.