The probability that Amaka will pass an examination is \(\frac{3}{7}\) and that Bala will pass is \(\frac{4}{9}\). Find the probability that both will pass the examination.
- \(\frac{2}{21}\)
-
\(\frac{4}{21}\).
- \(\frac{5}{21}\)
- \(\frac{9}{21}\)
The correct answer is: B
Explanation
Pr(Amaka passes) = \(\frac{3}{7}\), Pr(Bala passes) = \(\frac{4}{9}\).
Pr(both Amaka and Bala pass the exam) = \(\frac{3}{7}\) x \(\frac{4}{9}\) = \(\frac{4}{21}\).