A constant force of 40N acting on a body initially at rest gives an acceleration...

A constant force of 40N acting on a body initially at rest gives an acceleration of 0.1ms^-2 for 4s. Calculate the work done by the force

The correct answer is: C

X = ut + \(\frac{1}{2}\)at²

= (0 x 4) + (\(\frac{1}{2}\) x 0.1 x 4 x 4)

= 0.8m

workdone = force x distance

= 40 x 0.8

= 32J