Calculate the amount of heat required to convert 2kg of ice at 2oC to water at 0oC. [specific heat capacity of ice = 2090Jkg-1 oC-1, specific latent heat of fusion of ice = 333kJkg-1]
- 666J
- 8360J
- 666 000J
-
674 360J
The correct answer is: D
Explanation
Q = mL + mc\(\theta\)= (2 x 333000) + (2 x 2090 x 2)
= 674 360J